Tensor derivative

(Difference between revisions)
Jump to: navigation, search
m (Definition)
Line 1: Line 1:
{{Authors|Jost Eschenburg}}{{Stub}}
{{Authors|Jost Eschenburg}}{{Stub}}
== Definition ==
+
==Definition ==
<wikitex>;
<wikitex>;
Let $M$ be a smooth manifold and $E,E'$ vector bundles over $M$, both equipped with a [[Covariant derivative|covariant derivative]] $\nabla$.
Let $M$ be a smooth manifold and $E,E'$ vector bundles over $M$, both equipped with a [[Covariant derivative|covariant derivative]] $\nabla$.

Revision as of 13:16, 15 March 2013

The user responsible for this page is Jost Eschenburg. No other user may edit this page at present.

This page has not been refereed. The information given here might be incomplete or provisional.

1 Definition

Let M be a smooth manifold and E,E' vector bundles over M, both equipped with a covariant derivative \nabla. Then the vector bundle \textup{Hom}(E,E') of bundle homomorphisms (sometimes called tensors) inherits another covariant derivative \nabla : \Gamma TM \times \Gamma\textup{Hom}(E,E') \to \Gamma\textup{Hom}(E,E') called the tensor derivative which is defined as follows:

(\nabla_XT)s = \nabla_X(Ts) - T(\nabla_Xs)(1)

for any X \in \Gamma TM and s\in \Gamma E. The definition is made such that the application of tensors (sections in \textup{Hom}(E,E')) to sections in E satisfies the Leibniz product rule:

\nabla_X(Ts) = (\nabla_XT)s + T(\nabla_Xs)( )

The corresponding curvature tensors of the bundles E, E' and \textup{Hom}(E,E') are related similarly:

(R(X,Y)T)s = R(X,Y)Ts - T(R(X,Y)s)(2)

for any X,Y \in \Gamma TM and s\in \Gamma E.

2 References

Personal tools
Namespaces
Variants
Actions
Navigation
Interaction
Toolbox