Π-trivial map

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(First change to explain how the two perspectives of lifts and paths relate to each other)
(Finished the rest of relating lifts to paths)
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This page is based on \cite{Ranicki2002}. A map $f:N^n\to M^m$ between manifolds represents a homology class $f_*[N] \in H_n(M)$. Let $(\widetilde{M},\pi,w)$ be an [[Oriented cover|oriented cover]] with covering map $p:\widetilde{M} \to M$. If $f$ factors through $\widetilde{M}$ as $f= p\circ \widetilde{f}: N \to \widetilde{M}\to M$ then $f$ represents a homology class $\widetilde{f}_*[N]\in H_n(\widetilde{M})$. Note that a '''choice''' of lift $\widetilde{f}$ is required in order to represent a homology class.
This page is based on \cite{Ranicki2002}. A map $f:N^n\to M^m$ between manifolds represents a homology class $f_*[N] \in H_n(M)$. Let $(\widetilde{M},\pi,w)$ be an [[Oriented cover|oriented cover]] with covering map $p:\widetilde{M} \to M$. If $f$ factors through $\widetilde{M}$ as $f= p\circ \widetilde{f}: N \to \widetilde{M}\to M$ then $f$ represents a homology class $\widetilde{f}_*[N]\in H_n(\widetilde{M})$. Note that a '''choice''' of lift $\widetilde{f}$ is required in order to represent a homology class.
By covering space theory (c.f. \cite{Hatcher2002|Proposition 1.33}) a map $f:N\to M$ can be lifted to $\widetilde{M}$ if and only if $f_*(\pi_1(N)) \subset p_*(\pi_1(\widetilde{M}))$, i.e. if and only if the composition $q\circ f_*:\pi_1(N)\to \pi_1(M) \to \pi$ is trivial for $q:\pi_1(M)\to \pi_1(M)/\pi_1(\widetilde{M}) = \pi$ the quotient map.
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Let $b_1$ be a basepoint of $N$. By covering space theory (c.f. \cite{Hatcher2002|Proposition 1.33}) a map $f:N\to M$ can be lifted to $\widetilde{M}$ if and only if $f_*(\pi_1(N,b_1)) \subset p_*(\pi_1(\widetilde{M},\widetilde{f(b_1)}))$, i.e. if and only if the composition $q\circ f_*:\pi_1(N,b_1)\to \pi_1(M,f(b_1)) \to \pi$ is trivial for $q:\pi_1(M,f(b_1))\to \pi:=\pi_1(M,f(b_1))/\pi_1(\widetilde{M},\widetilde{f(b_1)})$ the quotient map.
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The group $\pi$ is well-defined for any choice of lift $\widetilde{f(b_1)}$ since $p:\widetilde{M}\to M$ is a regular covering and changing the basepoint in $\widetilde{M}$ to a different lift corresponds to conjugating $\pi_1(\widetilde{M},\widetilde{f(b_1)})$ by some $g\in \pi_1(M,f(b_1))$.
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== Definition ==
== Definition ==
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Let $M$ be an $m$-dimensional manifold and let $(\widetilde{M},\pi,w)$ be an [[Oriented cover|oriented cover]]. A '''$\pi$-trivial map''' $f:N^n\to M^m$ is a map from an oriented manifold $N$, together with a choice of lift $\widetilde{f}:N \to \widetilde{M}$, such that the composite
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Let $M$ be an $m$-dimensional manifold and let $(\widetilde{M},\pi,w)$ be an [[Oriented cover|oriented cover]]. A '''$\pi$-trivial map''' $f:N^n\to M^m$ is a map from an oriented manifold $N$ with basepoint $b_1$ such that the composite
$$\xymatrix{
$$\xymatrix{
\pi_1(N) \ar[r]^-{f_*} & \pi_1(M) \ar[r] & \pi
+
\pi_1(N,b_1) \ar[r]^-{f_*} & \pi_1(M,f(b_1)) \ar[r] & \pi
}$$
}$$
is trivial.
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is trivial, together with a choice of lift $\widetilde{f}:N \to \widetilde{M}$.
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== Properties ==
== Properties ==
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== Lifts and paths - two alternative perspectives ==
== Lifts and paths - two alternative perspectives ==
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Since $\pi$ is the group of deck transformations of $\widetilde{M}$, the set of lifts $\{\widetilde{f}:N\to \widetilde{M}\}$ is non-canonically isomorphic to $\pi$ with the group structure determined by the action of $\pi$ once an identity element lift $\widetilde{f}_{id}$ has been chosen. In this way the choice of lift that is included as part of the data of a $\pi$-trivial map can be thought of as a choice of isomorphism $$ \begin{array}{rcl} \{\widetilde{f}:N\to \widetilde{M}\} & \stackrel{\simeq}{\longrightarrow} & \pi \\ \widetilde{f} & \mapsto & g\;s.t.\; \widetilde{f} = g\widetilde{f}_{id}.\end{array}$$
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Rather than taking a lift as part of the data for a $\pi$-trivial map we could instead take an equivalence class of paths in $M$ as is explained in this section. Since $\pi$ is the group of deck transformations of $\widetilde{M}$, the set of lifts $\{\widetilde{f}:N\to \widetilde{M}\}$ is non-canonically isomorphic to $\pi$ with the group structure determined by the action of $\pi$ once a choice of lift $\widetilde{f}_{id}$ has been chosen to represent the identity element. In this way the choice of lift that is included as part of the data of a $\pi$-trivial map can be thought of as a choice of isomorphism $$ \begin{array}{rcl} \{\widetilde{f}:N\to \widetilde{M}\} & \stackrel{\simeq}{\longrightarrow} & \pi \\ \widetilde{f} & \mapsto & g\;s.t.\; \widetilde{f}(b_1) = g\widetilde{f}_{id}(b_1).\end{array}$$
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Let $b$ be a basepoint of $M$. The set of homotopy classes of paths from $b$ to $f(b_1)$ is non-canonically isomophic to $\pi_1(M,b)$. An isomorphism is defined by a choice of path $[w_{id}]$ to represent the identity element: $$\begin{array}{rcl} \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}& \to & \pi_1(M,b)\\ [w] &\mapsto & [w_{id}^{-1}*w],\end{array}$$where $*$ denotes concatenation of paths and $w_{id}^{-1}$ is the path $w_{id}$ in reverse. Let $\widetilde{b}$ be a basepoint of $\widetilde{M}$ that is a lift of $b$.
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Define an equivalence relation $\sim$ on this set by saying $$[w]\sim[w^\prime] \iff [w^{-1}*w^\prime] \in p_*(\pi_1(\widetilde{M},\widetilde{b})).$$ The above isomorphism given by choosing $[w_{id}]$ descends to give an isomorphism $$\{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim \;\longrightarrow\; \pi_1(M,b)/\pi_1(\widetilde{M},\widetilde{b})\cong \pi,$$ where we use the same choice of path $[w_{id}]$ to identify $\pi_1(M,b)/\pi_1(\widetilde{M},\widetilde{b}) $ with $\pi_1(M,f(b_1))/\pi_1(\widetilde{M},\widetilde{f(b_1)})=\pi$.
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Thus a choice of lift $\widetilde{f}:N\to \widetilde{M}$ corresponds to a choice of homotopy class of paths from $b$ to $f(b_1)$ modulo $\pi_1(\widetilde{M})$. A choice of lift $\widetilde{b}$ defines a bijection of sets $$\{\widetilde{f}:N\to \widetilde{M}\} \longleftrightarrow \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim$$ as follows. Given a choice of lift $\widetilde{f}$ choose any path $\widetilde{w}:I \to \widetilde{M}$ from $\widetilde{b}$ to $\widetilde{f}(b_1)$. Take the equivalence class of $p(\widetilde{w})$ which is a path in $M$ from $b$ to $f(b_1)$. Conversely given a choice of class $$[w]\in \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim$$ choose any representative $w:I \to M$. This lifts uniquely to a path $\widetilde{w}$ starting at $\widetilde{b}$. Define a lift $\widetilde{f}$ by setting $\widetilde{f}(b_1):= \widetilde{w}(1)$. Note this map is well-defined since different choices of representative $w$ may differ by elements of $\pi_1(\widetilde{M},\widetilde{b})$ but their lifts will still end at the same point.
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To sum up we have the following diagram of non-canonical isomorphisms and bijections
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$$\xymatrix{ \{\widetilde{f}:N\to \widetilde{M}\} \ar@{<->}[rr]^-{\widetilde{b}} \ar[dr]_-{\widetilde{f}_{id}} && \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim \ar[dl]^-{[w_{id}]} \\ & \pi & }.$$ Each map is obtained by making a choice and any two choices uniquely determine the third with the diagram commuting, so with two choices made the horizontal bijection is in fact an isomorphism of groups.
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Revision as of 15:59, 2 May 2013

This page has not been refereed. The information given here might be incomplete or provisional.

Contents

1 Introduction

This page is based on [Ranicki2002]. A map f:N^n\to M^m between manifolds represents a homology class f_*[N] \in H_n(M). Let (\widetilde{M},\pi,w) be an oriented cover with covering map p:\widetilde{M} \to M. If f factors through
Tex syntax error
as f= p\circ \widetilde{f}: N \to \widetilde{M}\to M then f represents a homology class \widetilde{f}_*[N]\in H_n(\widetilde{M}). Note that a choice of lift \widetilde{f} is required in order to represent a homology class. Let b_1 be a basepoint of N. By covering space theory (c.f. [Hatcher2002, Proposition 1.33]) a map f:N\to M can be lifted to
Tex syntax error
if and only if f_*(\pi_1(N,b_1)) \subset p_*(\pi_1(\widetilde{M},\widetilde{f(b_1)})), i.e. if and only if the composition q\circ f_*:\pi_1(N,b_1)\to \pi_1(M,f(b_1)) \to \pi is trivial for q:\pi_1(M,f(b_1))\to \pi:=\pi_1(M,f(b_1))/\pi_1(\widetilde{M},\widetilde{f(b_1)}) the quotient map. The group \pi is well-defined for any choice of lift \widetilde{f(b_1)} since p:\widetilde{M}\to M is a regular covering and changing the basepoint in
Tex syntax error
to a different lift corresponds to conjugating \pi_1(\widetilde{M},\widetilde{f(b_1)}) by some g\in \pi_1(M,f(b_1)).

2 Definition

Let M be an m-dimensional manifold and let (\widetilde{M},\pi,w) be an oriented cover. A \pi-trivial map f:N^n\to M^m is a map from an oriented manifold N with basepoint b_1 such that the composite

\displaystyle \xymatrix{   \pi_1(N,b_1) \ar[r]^-{f_*} & \pi_1(M,f(b_1)) \ar[r] & \pi  }

is trivial, together with a choice of lift \widetilde{f}:N \to \widetilde{M}.

3 Properties

A map f:N\to M that factors through
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must map all of N to the same sheet of
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, hence the pullback satisfies
\displaystyle f^*\widetilde{M} \cong N\times \pi.
Choosing where to lift a single point determines a lift \widetilde{f}:N \to \widetilde{M}, which thought of as a map from N\times \{1\} \subset N \times \pi extends equivariantly to a lift \widetilde{f}:\widetilde{N}:=N\times \pi \to \widetilde{M}.

4 Lifts and paths - two alternative perspectives

Rather than taking a lift as part of the data for a \pi-trivial map we could instead take an equivalence class of paths in M as is explained in this section. Since \pi is the group of deck transformations of
Tex syntax error
, the set of lifts \{\widetilde{f}:N\to \widetilde{M}\} is non-canonically isomorphic to \pi with the group structure determined by the action of \pi once a choice of lift \widetilde{f}_{id} has been chosen to represent the identity element. In this way the choice of lift that is included as part of the data of a \pi-trivial map can be thought of as a choice of isomorphism
\displaystyle  \begin{array}{rcl} \{\widetilde{f}:N\to \widetilde{M}\} & \stackrel{\simeq}{\longrightarrow} & \pi \\ \widetilde{f} & \mapsto & g\;s.t.\; \widetilde{f}(b_1) = g\widetilde{f}_{id}(b_1).\end{array}
Let b be a basepoint of M. The set of homotopy classes of paths from b to f(b_1) is non-canonically isomophic to \pi_1(M,b). An isomorphism is defined by a choice of path [w_{id}] to represent the identity element:
Tex syntax error
where * denotes concatenation of paths and w_{id}^{-1} is the path w_{id} in reverse. Let \widetilde{b} be a basepoint of
Tex syntax error
that is a lift of b. Define an equivalence relation \sim on this set by saying
\displaystyle [w]\sim[w^\prime] \iff [w^{-1}*w^\prime] \in p_*(\pi_1(\widetilde{M},\widetilde{b})).
The above isomorphism given by choosing [w_{id}] descends to give an isomorphism
\displaystyle \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim \;\longrightarrow\; \pi_1(M,b)/\pi_1(\widetilde{M},\widetilde{b})\cong \pi,
where we use the same choice of path [w_{id}] to identify \pi_1(M,b)/\pi_1(\widetilde{M},\widetilde{b}) with \pi_1(M,f(b_1))/\pi_1(\widetilde{M},\widetilde{f(b_1)})=\pi. Thus a choice of lift \widetilde{f}:N\to \widetilde{M} corresponds to a choice of homotopy class of paths from b to f(b_1) modulo \pi_1(\widetilde{M}). A choice of lift \widetilde{b} defines a bijection of sets
\displaystyle \{\widetilde{f}:N\to \widetilde{M}\} \longleftrightarrow \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim
as follows. Given a choice of lift \widetilde{f} choose any path \widetilde{w}:I \to \widetilde{M} from \widetilde{b} to \widetilde{f}(b_1). Take the equivalence class of p(\widetilde{w}) which is a path in M from b to f(b_1). Conversely given a choice of class
\displaystyle [w]\in \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim
choose any representative w:I \to M. This lifts uniquely to a path \widetilde{w} starting at \widetilde{b}. Define a lift \widetilde{f} by setting \widetilde{f}(b_1):= \widetilde{w}(1). Note this map is well-defined since different choices of representative w may differ by elements of \pi_1(\widetilde{M},\widetilde{b}) but their lifts will still end at the same point.

To sum up we have the following diagram of non-canonical isomorphisms and bijections

\displaystyle \xymatrix{ \{\widetilde{f}:N\to \widetilde{M}\} \ar@{<->}[rr]^-{\widetilde{b}} \ar[dr]_-{\widetilde{f}_{id}} && \{[w:I\to M]: w(0)=b,\,w(1)=f(b_1)\}/\sim \ar[dl]^-{[w_{id}]} \\ & \pi & }.
Each map is obtained by making a choice and any two choices uniquely determine the third with the diagram commuting, so with two choices made the horizontal bijection is in fact an isomorphism of groups.

5 Examples

...

6 References

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