Talk:Circle actions on 3-manifolds (Ex)

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(Created page with "<wikitex>; Insight: Try to quotient the manifold by the action. Note that you get something that looks kind of reasonable but isn't a manifold. Guess: The isotropy groups mus...")
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Insight: Try to quotient the manifold by the action. Note that you get something that looks kind of reasonable but isn't a manifold.
Insight: Try to quotient the manifold by the action. Note that you get something that looks kind of reasonable but isn't a manifold.
Guess: The isotropy groups must all be the same. Consider a point, then the isotropy groups of its neighborhood are the same as its own. Same thing for the boundary of an (open) region of fixed isotropy groups, so the set with identical isotropy groups is both open and closed. Then, the isotropy groups must in fact be $Z_n$. Then turn the $S^1$ action into one with trivial isotropy groups. Now try to take a cross section.
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Guess: The isotropy groups must all be the same. Consider a point, then the isotropy groups of its neighborhood are the same as the point's. Consider the same method for a point on the boundary of an (open) region of fixed isotropy groups; this shows the set with identical isotropy groups is both open and closed. Then, the isotropy groups must in fact be $Z_n$. Then turn the $S^1$ action into one with trivial isotropy groups. Now try to take a cross section (how?).
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Revision as of 07:19, 9 January 2019

Insight: Try to quotient the manifold by the action. Note that you get something that looks kind of reasonable but isn't a manifold.

Guess: The isotropy groups must all be the same. Consider a point, then the isotropy groups of its neighborhood are the same as the point's. Consider the same method for a point on the boundary of an (open) region of fixed isotropy groups; this shows the set with identical isotropy groups is both open and closed. Then, the isotropy groups must in fact be Z_n. Then turn the S^1 action into one with trivial isotropy groups. Now try to take a cross section (how?).

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