Talk:Circle actions on 3-manifolds (Ex)

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Revision as of 07:19, 9 January 2019 by Kevin Yin (Talk | contribs)
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Insight: Try to quotient the manifold by the action. Note that you get something that looks kind of reasonable but isn't a manifold.

Guess: The isotropy groups must all be the same. Consider a point, then the isotropy groups of its neighborhood are the same as the point's. Consider the same method for a point on the boundary of an (open) region of fixed isotropy groups; this shows the set with identical isotropy groups is both open and closed. Then, the isotropy groups must in fact be Z_n. Then turn the S^1 action into one with trivial isotropy groups. Now try to take a cross section (how?).

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