Obstruction classes and Pontrjagin classes (Ex)

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== Question ==
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<wikitex>;
Take the stable vector bundle over the $4i$-sphere corresponding to the generator of $\pi_{4i} BO = \mathbb{Z}$. What's its $i$-th Pontryagin class in $H^{4i}(S^{4i}) \cong \mathbb{Z}$ ?
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Take the stable vector bundle $\xi$ over the $4i$-sphere corresponding to a generator of $\pi_{4i}(BO) = \mathbb{Z}$. By defintion, the the primary obstruction to trivialising $\xi^{4i}$ is a cohomology class $x \in H^{4i}(S^{4i}; \pi_{4k-1}(O)) = H^{4i}(S^{4i})$ which generates $H^{4i}(S^{4i}) \cong \mathbb{Z}$.
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== Answers ==
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{{beginthm|Exercise}}
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Determine the $i$-th integral Pontryagin class of $\xi^{4i}$, $p_i(\xi) \in H^{4i}(S^{4i})$, in terms of $x$.
YOUR TEXT HERE ...
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{{endthm}}
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[[Category:Exercises]]
== Further discussion ==
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[[Category:Exercises with solution]]
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YOUR TEXT HERE ...
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== References ==
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{{#RefList:}}
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[[Category:Questions]]
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[[Category:Study questions]]
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Latest revision as of 01:00, 3 June 2014

Take the stable vector bundle \xi over the 4i-sphere corresponding to a generator of \pi_{4i}(BO) = \mathbb{Z}. By defintion, the the primary obstruction to trivialising \xi^{4i} is a cohomology class x \in H^{4i}(S^{4i}; \pi_{4k-1}(O)) = H^{4i}(S^{4i}) which generates H^{4i}(S^{4i}) \cong \mathbb{Z}.

Exercise 0.1. Determine the i-th integral Pontryagin class of \xi^{4i}, p_i(\xi) \in H^{4i}(S^{4i}), in terms of x.

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