Suspension of a symmetric complex (Ex)

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(Created page with "<wikitex>; Using the definition and the $\omega$ from Exercise 4 show that $$ S(\varphi)_0 = 0 $$ and $$ S(\varphi_{s+1}) = \pm \varphi_s $$ </wikitex> == References == {{#Ref...")
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<wikitex>;
<wikitex>;
Using the definition and the $\omega$ from Exercise 4 show that
+
Using the definition and the $\omega$ from Exercise [[Structured chain complexes III (Ex)]] show that
$$
$$
S(\varphi)_0 = 0
S(\varphi)_0 = 0
$$
$$
and
+
and for $s \geq 0$
$$
$$
S(\varphi_{s+1}) = \pm \varphi_s
S(\varphi_{s+1}) = \pm \varphi_s

Latest revision as of 12:49, 25 August 2013

Using the definition and the \omega from Exercise Structured chain complexes III (Ex) show that

\displaystyle  S(\varphi)_0 = 0

and for s \geq 0

\displaystyle  S(\varphi_{s+1}) = \pm \varphi_s

[edit] References

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