Surgery obstruction, Arf-invariant (Ex)

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Let $(K,\lambda,\mu)$ be a $(-1)$-symmetric unimodular quadratic form over $\Z$ so that $(K,\lambda)\cong H_{-1}(\Z^r)$ with canonical basis $\{e_1,\ldots, e_r,f_1,\ldots, f_r\}$. Recall that the quadratic refinement $\mu: K \to \Z_2$ is a function such that for all $x,y\in K$, $$\mu(x+y) = \mu(x)+\mu(y) + \lambda(x,y)\quad (\mathrm{mod}\;2).$$ Define the '''Arf invariant''' of $(K,\lambda,\mu)$ by $$A(K,\lambda,\mu) := \sum_{i=1}^r\mu(e_i)\mu(f_i) \in \Z_2.$$ Prove that the Arf invariant is well-defined and defines an isomorphism $$A:L_2(\Z)\cong \Z_2.$$
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'''Hint:''' Start by classifying quadratic forms on $\Z^2$, use induction and also count the size of the sets $\mu^{-1}(0)$ and $\mu^{-1}(1)$.
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== References ==
== References ==

Latest revision as of 21:18, 25 August 2013

Let (K,\lambda,\mu) be a (-1)-symmetric unimodular quadratic form over \Z so that (K,\lambda)\cong H_{-1}(\Z^r) with canonical basis \{e_1,\ldots, e_r,f_1,\ldots, f_r\}. Recall that the quadratic refinement \mu: K \to \Z_2 is a function such that for all x,y\in K,
\displaystyle \mu(x+y) = \mu(x)+\mu(y) + \lambda(x,y)\quad (\mathrm{mod}\;2).
Define the Arf invariant of (K,\lambda,\mu) by
\displaystyle A(K,\lambda,\mu) := \sum_{i=1}^r\mu(e_i)\mu(f_i) \in \Z_2.
Prove that the Arf invariant is well-defined and defines an isomorphism
\displaystyle A:L_2(\Z)\cong \Z_2.

Hint: Start by classifying quadratic forms on \Z^2, use induction and also count the size of the sets \mu^{-1}(0) and \mu^{-1}(1).

[edit] References

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