Elementary matricies (Ex)

(Difference between revisions)
Jump to: navigation, search
m
m
Line 1: Line 1:
<wikitex>;
<wikitex>;
Let $R$ be an associative ring with unit and recall that an ''elementary matrix'' over $R$ is a square matrix of the form
+
Let $R$ be an associative ring with unit and recall that an ''elementary matrix'', $E$, over $R$ is a square matrix of the form
$$ E = \text{Id}_n + a e_{ij} $$
$$ E = \text{Id}_n + a e_{ij} $$
where $\text{Id}_n$ is the $n \times n$ identity matrix, $a \in R$ and $e_{ij}$ is the matrix with zeros in all places except $(i, j)$ where $i \neq j$. Clearly each elementary matrix if invertible and so gives and element $E \in GL(R)$ where
where $\text{Id}_n$ is the $n \times n$ identity matrix, $a \in R$ and $e_{ij}$ is the matrix with zeros in all places except $(i, j)$ where $i \neq j$. Clearly each elementary matrix if invertible and so gives and element $E \in GL(R)$ where

Revision as of 18:58, 23 March 2012

Let R be an associative ring with unit and recall that an elementary matrix, E, over R is a square matrix of the form

\displaystyle  E = \text{Id}_n + a e_{ij}

where \text{Id}_n is the n \times n identity matrix, a \in R and e_{ij} is the matrix with zeros in all places except (i, j) where i \neq j. Clearly each elementary matrix if invertible and so gives and element E \in GL(R) where

\displaystyle GL(R) = GL_{\infty}(R) : = \text{lim}_{n \to \infty}GL_n(R)

is the limit of the invertible matricies.

Exercise 0.1. Prove that E(R)=[GL(R),GL(R)], where E(R)\subset GL(R) is the subgroup generated by all elements in GL(R) which are represented by elementary matrices.

Hint 0.2. For A\in GL(m,R) and B\in GL(n,R) write the matrix

\displaystyle  \left( \begin{array}{cc} ABA^{-1}B^{-1} & 0\\ 0 & I \end{array} \right)

as a product of elementary matrices

\displaystyle  \left( \begin{array}{cc} I & X\\ 0 & I \end{array} \right) =  \prod_{i=1}^{m}\prod_{j=1}^{n} (I+x_{ij}E_{i,j+m})

where X=(x_{ij}) is an m\times n matrix.

Recall that K_1(R) is defined to be the abelian group

\displaystyle  K_1(R) : = GL(R)_{ab} = GL(R)/[GL(R), GL(R)].

Exercise 0.3. Prove that K_1(\Zz) = \{ \pm 1 \}.

References

Personal tools
Namespaces
Variants
Actions
Navigation
Interaction
Toolbox