Novikov additivity I (Ex)

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(Created page with "<wikitex>; Let $(Y,X)$ be a $2n$-dimensional manifold with boundary, $n = 2k$. Consider the homomorphism $\varphi \colon H^{n} (Y,X) \rightarrow H^{n} (X)$ and denote $\wideha...")
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<wikitex>;
<wikitex>;
Let $(Y,X)$ be a $2n$-dimensional manifold with boundary, $n = 2k$. Consider the homomorphism $\varphi \colon H^{n} (Y,X) \rightarrow H^{n} (X)$ and denote $\widehat{H}^{n} (Y)$ the image of $\varphi$. Coefficients are understood to be in $\mathbb{R}$.
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Let $(Y,X)$ be a $2n$-dimensional manifold with boundary, $n = 2k$. Consider the homomorphism $\varphi \colon H^{n} (Y,X) \rightarrow H^{n} (X)$ and denote $\hat{H}^{n} (Y)$ the image of $\varphi$. Coefficients are understood to be in $\mathbb{R}$.
The middle dimensional intersection form
The middle dimensional intersection form
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H^{n} (Y) \otimes H^{n} (Y) \rightarrow \mathbb{R}
H^{n} (Y) \otimes H^{n} (Y) \rightarrow \mathbb{R}
$$
$$
is degenerate in general. Show that the intersection form $B$ on $\widehat{H}^{n} (Y)$ defined by
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is degenerate in general. Show that the intersection form $B$ on $\hat{H}^{n} (Y)$ defined by
$$
$$
B(\varphi (a), \varphi (b)) = \langle a \cup b , [Y] \rangle
B(\varphi (a), \varphi (b)) = \langle a \cup b , [Y] \rangle

Revision as of 10:05, 29 May 2012

Let (Y,X) be a 2n-dimensional manifold with boundary, n = 2k. Consider the homomorphism \varphi \colon H^{n} (Y,X) \rightarrow H^{n} (X) and denote \hat{H}^{n} (Y) the image of \varphi. Coefficients are understood to be in \mathbb{R}.

The middle dimensional intersection form

\displaystyle  H^{n} (Y) \otimes H^{n} (Y) \rightarrow \mathbb{R}

is degenerate in general. Show that the intersection form B on \hat{H}^{n} (Y) defined by

\displaystyle  B(\varphi (a), \varphi (b)) = \langle a \cup b , [Y] \rangle

is a non-degenerate symmetric bilinear form and let us define the signature \textup{Sign} (Y) to be the signature of this form.

Suppose that we have also another 2n-dimensional manifold Y' with boundary -X. Form the closed manifold Z = Y' \cup_{X} Y. Show that

\displaystyle  \textup{Sign} (Z) = \textup{Sign} (Y') + \textup{Sign} (Y).

Hint: section 7 of ASIT III

References

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