Supplement III (Ex)

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Denote N(\sigma) = N \cap (|D(\sigma,K)| \ast |\overline K|) for \sigma \in K. Then we have the dissection N = \cup_{\sigma \in K} N(\sigma). Show that the retraction r respects the dissections of N and |K|

\displaystyle    r|_{N(\sigma)} = r(\sigma) \colon N(\sigma) \rightarrow |D(\sigma,K)|.

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